Perhaps the diversified images of the glyphs have no further purpose, than to differentiate them into 46 dissimilar species for counting functions (17 +12 +17). What is then the heritage of the symbols? that is quite a different matter.*

At the left side of this illustration I arrange the signs (signs=glyphs) in groups of nine signs, that depict: humans, animals, crops, tools, and various artifacts. All signs suit fine into these catagories. What is more spectacular is that they, in accordance with the true inscription, belong together two by two, in what I call "stem-elements" (right). which furthermore are in compliance with three stem-groups. The stems turn up to be a very efficient instrument for the understanding of the disc. -Before you'll find no reliable indicators, in whatever enumerations you try, whereas the inscription literally 'explodes' in categories of divisibility by eleven, after the acceptance of my 22 stem-forms, 'never known of before'!. Such common-denominator normally indicates a classical key, what codes concern (cf. Ventris grid of syllables). -This rule does not disappoint in this enigma either.
I define a stem as: A sequence of two 'and only two signs', that occur in at least one more signgroup. A stem is not allowed to overlap any other stem, which is already confirmed by a higher frequency
[Or simply choose the correct species of 70 stem-elements, without knowing forehand, that it being the great goal!] -you certainly know it very soon afterwards- , due to enumerations!
NB! If you try this definition with some paragraphs based on language, you typically shall get clusters of unbreakable signs, and too few non-inverted stems, in great contrast to the tendency of an order of signs inside the 22 stem-forms; only two out of the thirty stem-signs occur, a single time each, in both positions inside the various stems, they are "sign F and Q".
It is naive, if not suspect, to argue that this unravelling of the 70 stems of two signs is just a two way choice 'either language or something else'. They were a million way choice. There is no comparison between the common process of getting familiar with an inscription, for instance by recognizing that B22 and B29 are somehow related groups, or to observe that B21 is a repetiton of B26 etc. ,cf. Günther Ibsen, 1926. -followed up by Leon Pomerance, 1976 contra the process of realising the absolute amount of 70 stem-elements of 'always' two signs, they are a countable and sophisticated product. If the 22 were known about before 1985, lots of periodicals would have announced such turning point immediately years ago.
Research: In the early nineteen-eighties, I consulted the university libraries to test the novelty of my discovery.
Günther Neumann's "Zum Forchungsstand beim 'Diskos von Phaistos". Kadmos, 1968, told me that my discovery of the exact 22 stem-forms was unknown until then. By the same token, Leon Pomerance's "An interpretation of Astronomical symbols". Paul Åstrøms förlag, 1976., assured me that all my ideas were unknown.
It is only logic to declare, that had my "discovery" of the exact 22 stem-forms of two signs been ratified in say 1978, by others, then my 29 day-calendar had been traced down in a matter of months (certaintly before 1985).- It was not-. Only to be explained by, that my discovery had not been manifested at that time, in 1978.
N.B. [In a limited material as this one, others approaches shall always remind you of discarded ideas of your own. -Annoying, but this is an illusion]. Only the exact 22 stems-forms of two signs ignites the prosperous count.*

BINGO!- [The exact 22 stem-forms were not in existence before 1982. They were born by me out of nothing, with all the guts that it takes. They represented from the first moment, the long-awaited turning-point - In minor scale a Big Bang !]
Foremost stands my essential discovery of "the 22 stem-forms" as the answer to this disc and the shocking results, that they bring along. - Secondary we got all other of my perfectionist illustrations 'often in variations' and the aphoristic remarks to match. Those, together with my videos, should be taken as 'in spirit sketches' to be called "Ariadne's threads" so making us assured, that we are on the right track.
My drawings are all monumental, and could easily stand by themselves as single notifications, in what ever periodical you choose; In that they are direct consequences of the 70 stems. All leading to the 365-day calendar.

If you as an editor of a good standing periodical see this page and take interest in my discovery, then please contact me for a solitary publication of my proposal for an alternative alphabetic notation. This would be a helpful introduction for everyone, who wants to study these hieroglyphs, not as syllables, but as quantities, and a great support for me. A text should then be reduced to a brief editorial comment. - That would be perfection. -



E.F.A.N.K. The genuin stems together with the reduced stems have the amount of 145 elements, expanded to 290 units. The non-stem elements are of 58 units, [elements(70+75+29)x2=348,+17 diminished thorns]
In this way I arrange all the 61 dissimilar elements into four groups. Essential three stem-groups. As seen, the inscription consist of 60+1 dissimilar elements, the same number as the amount of signgroups; and a 6th part of 366 days.
Once again -What you see above is the 22 different stem-elements of two signs, and the 38 shortform elements of only one sign (+ the seven-teen subordinated thorns).
If you accept my specialized stems, you have to accept the whole package, because all my observations are just consequences of the stems. So if I had had a mild fortune, my humble request complied with from the start for a proper publication of my coded alphabetic notation of the stems, those exact same consequences would have been confirmed from every quarter of the globe by honest people in a matter of months (what a fulfilment of the key!). Now ridders of my fortune rule instead.
Everyone who was profoundly occupied in the past done with this very same topic must have had the same alert over and over again, like I did, that they were dealing with some mathematical construction. then overhearing this signal, they turned back to their established grammatical studies over the topic. Those are my witnesses.
Annotation : After a span of one-hundred years still no 'mutual consistency' among the many linguistic attempts to cut the knot, did show. A suspicion thrust forward, that 'the linguistic perception' was out of course, that the very disc might depict a calculation of some kind instead. On that notion a new generation af noblemen groped their ways with highly theoretic calendar-proposals, zodiacs, and astrolabia (only fantasy fix a limit). No-one ought to disagree, when I claim, that only by my 'breaking discovery' of stems of two signs together with abbreviated stems, a mathematical foundation appears, and at the same time filling in the gap from an amputated model to a complete 365-day calendar. -This vessel left over for others to polish to perfection, after my discovery is suitably published of course, and please let me know.
[This breaking discovery of mine should be coeval with Michael Ventris famous grid of syllables from 1950, that soon after was verified by the excavation of 1000 more written tablets in linear-B from Pylos].
The main argument against any deciphering of this item is, that more external material are needed to confirm a solution. -Yes, but this assumption in particular counts, if the preconceived idea that those glyphs are syllables, is not false. -Does'nt it?
Which one is most convincing; A 243 letters paragraph (if that is the claim) approximately matching this disc inside an ancient text in lack of vowels and apostrophes:

Or a luni-solar calendar of 12 months, each month of 29 days inside 5 weeks ( and with an additional 61th intercalary week of 6 days for the moon (354 days), this construction having inserted eleven extra days during the year for the sun (365 days)?
NB, The double spiral was, during the Bronze age, and still this very day, the natural symbol for the equinoctial cycle.


The 50 cartouches in the top, on the grey-coloured floor of this drawing, are the 22 pair of stem-signgroups, and the six unpaired stem-signgroups. together containing 290 units, inclusive absent units (in blue) and thorns. The succession of those 50 cartouches is modestly re-arranged 'from the original succession on the disc', with the purpose to keep the 22 pairs close connected, and also to gain five double months of 58 unit-days on line. [An average of 5 weeks and 29 days per month] The fifth double month uses 16 of the 17 thorns of the stem-signgroups to obtain the count up to its 58 units.
N.B. A01,A02,A03,A04,A05,A06 belong to side B. This is true only by my discovery of the 22 stem-forms. -This connection does not exist without!
Now the lower deck on the drawing with a pink floor holds the eleven non-stem-signgroups 'curiously located on uneven numbers', out of which eigth constitute a last sixth periode of 58 days. Is this sixth double month accumulating a reservoir for the superior calculation going on in the 50 stem-signgroups? Finally I try out this three non-stem signgroups in excess :B03, A13, and A18 as representatives for 17 orange epigomenal days in this 29 x12 moon-calendar. Curiously giving 29 signgroups on side A, and 29 signgroups on side B. Conclusion: Several interlaced systems framed by a calendar. This is as close as we get by now: A verifiable approximation of the truth to the question "What is the Phaistos disc about?". On this you can rely . Think about the gnomonical arrangement , think about the hierachical order of the elements, and do not forget how all the signgroups will be stitched together into one string 'no criss-cross'. Consider the splitting of time in shifts between 12 and 17.

[ Remind it all, because those are the brooks, which brought this river into existence ]


All 61 sign groups linked together in one single string by double stitch, never using the same sign in more connections, and not leaning on stems in particular, and with the two most common elements: the 13 times occurences of "BA", and the 17 diminished thorns not neccesary to obtain the chain. A landscape that does not correspond with language. [This paragraph in red holds 61 words as well. Exercise : chain those 61 words together into one string :-(]

I repeat : A first-rate demonstration of a non-grammatical content in a structure is this tabulation of the signgroups, which marks 30 pair of signgroups; Each pair, by components, tied together by an identical sign (marked blue). The two components of the pair have moreover each one offshoot (orange signs) to the 'next-floor' pairs, which possess exactly the same qualities 'one sign in common, each component with an offshoot to the next pair'. In this way all 61 signgroups are linked together into one single string. The most frequent elements are 'BA' with thirteen occurrences, and 'the thorns' with seventeen. Those two are easily isolated from the above countings. This chaining together make use of as much as 32 out of a total of 46 dissimilar signs (2/3) as links. -The disc possess 61 signgroups, out of which as many as 53 are 'inclusively' unrepeated.
If all the words in a piece of poetry or a prosaic text, chosen by random, could be linked together in one unbroken chain by double stitch! same as could those clusters of signs; Would'nt we then expect, that unknown disciplines inside philology had developed during time? For instance metaphorical translations of texts into unambiguous patterns, like the harmony of the spheres, or like Mandelbrot music? This is not the case in texts, otherwise opponents of my discovery would long ago have dished up with competitive examples from Literature, -but they stay mute; Whereas in systems alias protocols, ledgers, book-keeping by double entrance, various tables, such symmetries like 'a hollow pyramid' or 'a gnomonical arrangement' are given by themselves. Thereby this classical break-through is in reality settled. Follow-up-questions like, what is the origin of the subject? How old? Which sign for the harvest moon? An interwoven text simultaneously? Or is it a fake? etc. - you name it - are of course secondary questions. "Discovery" is without comparative degree! - By the way, what postpones the reactions and the approvals of this rare discovery of mine?
[Shame to the highly educated, but immature persons, excuses inadequate, who tempt such backward thing to happen, whatever reasons they bring forward. Kind of childish excommunication out of envy; as if my advancements into the heart of this topic was on black-list. The truth is rather that my discovery is covetuosly pursued. -Hope it shall not paste! - As you all know: I did deliver the "answer" to this famous riddle of the Minoans, at the age of 34, in the year 1985, with the self-given intention to have it manifolded immediately by autograph]. Exactly like you would have wanted yourselves.*
Herostratus was a 4th-century BC Greek arsonist, who sought notoriety by destroying the Temple of Artemis, one of the Seven Wonders of the Ancient World.. Thus, Herostratus has become a metonym for someone who commits a criminal act in order to become famous … Damnatio memoriae (Wikipedia). -



The above arrangement is comparable to Dr. Christoph Henke's experiment:The hierarchy of the characters on the diskus of Phaistos (file.pdf).
In his paper from 2001, as I read it, he actually try to prove, that my hierarchical result cannot be reached, if the hieroglyphs represent grammar. Very pleasant to know. -The solution to the whole problem was to gather the signs two by two, instead of regarding each sign alone. The two signs inside the 22 stems-forms possess an order of precedence in themselves too. Perhaps his analysis could be an example of a result indirectly gained by my decipherment -a back-door-. That would be an example of why it is so dissatisfactory (cf.  Marianna Ridderstad. Anistoriton vol.12. 2010), that my decipherment was never received in a respectful way back in 1985. - Never referred to.
By chance I found this website from 1999 ,using two highly sophisticated drawings of mine in which I announce my 22 stemforms. - I do not see my name mentioned. It would also be nice to receive some royalties for my popular mantelpiece in LEGO of an hollow step-pyramid calendar.: For the first time the fundamental numbers of 61 sign-groups and 244 signs from the Phaistos disc are rediscovered in another calendrical construction.! *

(5) This hollow step-pyramid: 144+100(+64 +36 +16 + 4 + 1) =365. Eureka!



If those seventy stems really reflect the secret about this old enigma, if they so were the key and the first sure entry to this minoan secret, you would expect some kind of correspondence between the stem-signs inside and outside of the stems; and yes, that was exatly, what was found :
Comparing 'the unfolded arrangement' with a picture-lottery seems significant, in which the pair of stems, subsidiary all stems, are playing-squares (point 1, 2), and all other signs are pieces (pale skin colour). It is a familiar situation, that one or more pieces are missing. Let us imagine conversely, that we have had a mingling together with some outside pieces. We therefore charge ourselves with the task to sort out the pieces, that are in excess. The non-stem signs (point 5) have no correspondence with the playing squares, and are so to be sorted out without further ado. Putting down the pieces (point 3), where they fit into the squares (sky blue), will finaly leave us with nine pieces (point 4), which were represented in the squares, but they are now in excess, because the playing squares are already occupied. The dolphin (sign K) for instance is present in two stems, but it occurs four times independently, there are so to say two uncovering dolphins in excess. Those nine stemsigns are to be sorted out too, like the non-stemsigns. - So are the thorns (point 6). Of cause, this is not an argue in favour of the inscription as a picture-lottery, I just want to indicate, that a principle of a similar kind can be applied with success; that some complicated, but symmetrical proportions, between the signs on the basis of their functions, are unveiled.
*As regards positions, the sign ro the right inside a stem holds first position and vice versa.
How come the torso "Venus de Milo" be an ideal of beauty? Is'nt it because our sense of proportions approximately tell us, what she looked like?



By observing the numbers 18, 22 and 26, it struck me, that square-sides of respectively 10, 12 and 14 hold circumferences, which are related to these numbers. This compels an almost unambiguous and most expressive way, in which 'the unfolded situation' is to be arranged, as the signs of the 33 pair of stems are to be set up as circumferences in a quadratic framework 'the folded arrangement'. The upper half of the framework is uncovered components of stems, and the lowest part is those signs in stems, which have cover from the reduced stemsigns (point 3). As it does show, the covering signs do not only make up a gemination of the lowest part of the framework, they keep themselves within the areas in their half, which are marked out by the three stemgroups. I have divided the frame into six zones, each containing 22 signs. The six zones are symbolized by Aa, Ab, Ba, Bb and Ca, Cb. - Bb for instance is those 22 signs in second position, which are gathered in the bottom left-hand corner of the frame. Together with Ba, Bb is able to establish 22 covering stems, of which 11 are dissimilar.* the covering stemsigns (Bb, Cb, Ba) consist of 33 signs in first position and 33 signs in second position. The upper half (Aa, Ca, Ab) then get the same bisection of the positions, obviously.The zones Ca and Cb hold each 11 signs in both first and second position. Together they compose 22 stems crosswise of the median line. It is seen, that multiples of eleven are reflected in a lot of new facets, although there are some limited ways to castle the signs, within those by positions and stemgroups restricted areas. This gnomonical arrangement, I believe, is the most ideal way to illustrate those symmetrical proportions, which are unquestionably available in the inscription. Especially the arrangement substantiate the legitimacy of the three stemgroups. There are however irregularities to be mentioned: Stemgroup II holds 18 covering and 18 covered, but 22 uncovered signs; While stemgroup III has 22 and 22, but 18 signs. If you consider the inscription as a numerical system, it would probably had made a more convincing impression, if the equal conditions had been respectively: 18, 18 and 18 plus 22, 22 and 22, together with the 26, 26 and 26 signs of signgroup I; on the other hand the very irregularities may be promising for a more complex application, than a mere ornamental play with some imprints and their quantities, on the part of the designer of the Phaistos disc.


You'll find 70 stems in the inscription as a whole. As many as 66 of these stems are entering into stem-pairs, leaving 4 unpaired stems. Those 66 stems in pair fit into a frame, which I call the gnomonical arrangement (the figure above). - Stemgroup I is aqua, stemgroup II is yellow, stemgroup III is pink. In the same way. You will find 75 stem signs in total, which are disconnected from stems. 66 of those isolated stem signs suit into pairs with the signs inside of the 70 stems, giving 9 signs in excess. In other words: They will be covering exactly one half part of the components in the 66 stems , as a duplicate of the lower part of the arrangement. -All in all comparable to a picture-lottery. Harmony everywhere! manifesting itself as multiples of eleven. As shown in this Udjat video]
P.S. The two halves of the frame each have 22 connected stem-components, but they have 29 pair of signs.
Good-bye language!


Now I shall try the attempt to concentrate the genuine stems of two visible signs in the top of the frame. This is my method, and "the related gnomonical arrangement" is the result.
a) In the upper left of this diagram is seen the frame of the 66 pair of stems, called "the gnomonical arrangement". The 66x2 components are separated in black for the right, and red for the left position in stems.
b) In the middle section of the diagram the six corners (gnomons) are paired into three corners.
c) In the lower left diagram the reduced stem-components in black are placed in the bottom, while the calculated missing units in white are at top. d) In the middle section again the three gnomons are folded into three.
e) To the right is seen the related arrangement. The six colored gnomons are identical two by two so that 66 of the reduced stems become a copy of the 66 stems in pair. You may argue against this idea, that the vessel is fragmentary in its left corner, but still it is recognizable as what it is. So is Venus de Milo.

N.B. A provoking notion: The DNA-molecule carries the genetic code for any organism. -The 70 stems wear the instructions, which compel "the gnomonical arrangement". *
Fare thee well Darwin. ;-)



Comprehensive view : Ergo, the 66 paired stem-elements are arranged in the upper half of the above "related gnomonical arrangement". Now the inscription shows to be mischievous (this is probably the reason why its symmetries never have been acknowledged before), because the sign-materiale within the stem-elements also exists outside the stems, as isolated and singular symbols.
My great idea is then, that the isolated signs are abbreviations from stem-elements. I've placed those "reduced stems" in the lower part of the arrangement. All visible signs in the reduced stems are hold in black, as were the stems, and the abbreviated signs are painted light greyish. As you see 7 of the 9 reduced stems in excess (75-7) is replacing the misfitting 7 stemelements in the truncated upper left corner of this alternative frame.
Calculations and counter-checks are fundamental principles in building up ledgers. Or if the calendar is the primary factor of the inscription, then perhaps the hieroglyphs could be describing the movements of the sun versus the moon through the year, or a similar system of congruency. As it is, we got no-one to ask, and this gnomonical arrangement should carry in it the very solution to this riddle from the extinct Minoan world.

Be welcome calendar!


The 22 stem-forms are the key to the disc, the gnomonical arrangement is the documentation for this key, and the 29-day calendar is the answer to it all.

By replacing the seven red-coloured stems by the seven reduced stems in excess the related gnomonical arrangement became a sublime symmetrical construction. For instance its six gnomons are identical two by two, each gnomon containing 11 different stems and 22 stems in all.
On the other hand if you remove the seven red-coloured stems without any replacements, and count the amount of the pairs of stems, then the upper part has 29 such pairs, consisting of total 116 signs, so has the lower part 'the reduced stems', considering the 58 absent stem units that they hide. Outside the frame are now superfluous 29 stem-elements of two units, being 58 units (to the left). Finally 29 non-stem signs to be redoubled to 58 signs (to the right), rounding the total numbers of units up to 348, (116+116+116), not to forget the 17 thorns.
With this I have reverted to the calendar possibility. Each of the four halves, the fourth half being the absent units in the reduced stems, is systems of 29 well-organized pair of signs (58 components) and 8 immediately unpaired characters. Although, there is one condition for this complete symmetrical arrangement: That the obliterated reduced sign in A08 unambiguously is set to be the sign "P". Thus the Gnomonic arrangement compels the identity of the missing final character in A08.
N.B. Ergo calendrical 29 not only show in the shift 7, 8 in the succession of the sign-groups. It is also build into the basic functions of the pairs of stem-elements!
[Experts in ancient or current luni-solar calendars should rightly recognize with applauds my various calculations of 29]. * -The above diagram brings the link once again between the 70 stems and the 12 times 29 days calendar.
Doctor of Philology Professor, Emeritus Ernst Doblhofer, Die Entzifferung vershollener Schriften und Sprache (1961). About the Phaistos disk:
"Possibly a professional investigator will sooner or later win the laurels promised to the one who solves the riddle of this clay plaque, which can be seen today in the Heraclion Museum. Or perhaps a brilliant amateur will solve the mystery of the spiral images and, like a modern Theseus, find the way out of this new labyrinth of the island of Minos"

More brooks for the river.


Simply define 22 stem forms of two signs, and find all 70 stems hidden in the sign material of 244 signs. Consequently take a census of the isolated 75 stem signs, which do not possess the second units. The remaining materiale is of 29 non-stem signs, and 17 thorns. The Minoan calendar is reborn -: Those four numbers are all expressible through a shift between 12 and 17 -, (5,7,5,7,5)
70 stems =12 +17 +12 +17 +12 -, 75 reduced stems =17 +12 +17 +12 +17 -, 29 non-stem elements =12 +17 -, 17 thorns =17. Perhaps the diversified looks of the glyphs have no other purpose, than to differentiate them from one another into 46 dissimilar species ((17 +12 +17) for counting reasons.
[ If you study my illustrated consequences of the 70 stems, you must admit, that the concept for a calendar emerges, and that the calculations that lead to it, rules out the idea of phonetic signs to be present simultaneously.
This compels the conclusion, that the Phaistos disc is " a calendar construction containing countable quantities, which are redoubled ". Alltough the conclusion stay clear, -the full understanding of the details from those prehistoric days, will remain fragmentary. -Even the moon has its shadows].

Another prosperous brook.




I better comment this important illustration with both some words and some numbers. If I call the eight piles of two colours in the upper left, for the tableau, then the figure to the right is referred to as the foundation. First the tableau is made free of all 29 non-stem elements, these are the two waste piles in the bottom. Secondly I have also removed 12 stems and 17 reduced stem-elements, together containing 12 +17 +12 =41 signs ( the red and dark violet waste piles in the lower left). Now the tableau is composed of 58 stems and 58 expanded reduced stems with the total of 232 units (29 x8)* As seen, the waste is marked on the foundation too, except for the 4 unpaired stems and the 9 reduced stems in excess, that can be found in the lower right figure. Another detail of interest: having sorted out the waste from the inscription, results in that one signgroup on side B, and two on side A are emptied for signs, giving 29 sign-groups on both sides. -B19, -A07. and -A19
*If the reduced stems were not expanded, the shortform tableau would be of 174 visible signs (29 x6). This is 70 units from the actual Phaistos disc inscriptions 244 signs. (29x8, +12). Or you could say that if the 70 genuine stems were reduced each with one sign, the result would be the same number, 244 -70 =174. (29x6) -If 174 is redoubled, you end up with 348 (29 x12)
As you see, the illustration right above here is the corellation between those two systems all together. Such perfect co-ordinated systems are of course not there to be found by pure coincidence.

Some more consequences of the stems.
Some might wonder: How come it be, that 'this outlay for six double-months, as seen on the left side of the figure above, are interwoven on the disc with such a complexity? defined as non-stem elements, mirrages of stem elements in pairs, elements in excess, and more... -I don't know, (and believe me, I only need to care a little, those are parts of the confirming consequences of my discovery of the 22 stem-forms) it is a fact, that it is just 'what' they are in this 348+17 days calendar!

"The science of counting things is basically the discipline of turning problems into enumeration statements to find out if they can be solved this way".


E.F.A.N.K. The total count of elements is 174 (incl. reduced elements). Side A with 82, and side B with 92. 82/2=41, =12+17+12. 92/2=46 =17+12+17.
This above linear transcription, which constitute an eight month calendar, is the first step towards my demonstration of a 364-day calendar in the Phaistos disc. I ought to settle, that without adding the two initial "pearl strings" to the inscription (sign g) as genuine units, such possibility, as to proceed, by the way of trial and error, to a similar regular eight months calendar, do not exist. *
Nota bene: The four partitions of 31 pictographs hold in them the four unpaired elements (31-2)4.

[The peacock calendar is a two third part calendar, based on the abbreviations of the reduced stems. In its complete form it contains of 364 units, but some corrections need to be done, A08 =ZÆBA, A07 =/aiW . This gives an outlay of 243 symbols. If the Minoans did use this record for several centuries, they might have found more usages for the disc, so it is a possibility that one day archaeologists shall excavate an ancient copy of the Phaistos disc, this one missing the 8 symbols in the four unpaired stems. then only 235 symbols appear, those for the lunations in the 19 year solar calendar. Bringing the moon back to start on the firmament].
N.B. They might have used paint (later to be washed out) to mark a symbol for multiple purposes. The 45 dissimilar symbols could be star-markers in the sky with an distance of 8 degrees.

(1) A08 only contains 4 signs, and not 5.
(2) The northern or southern area contains an additional 18th thorn.
Signs and units are days, signgroups are equal to weeks. 7 or 8 signgroups with alternately 29 or 31 signs are months.

Move the 61th signgroup "A31" into the bull's eye, and unfold the two spirals to a single grand circle, that A30 is followed by B01 and B30 by A01. Such circle has a periphery of 240 signs.
Now displace the starting point from A01 one step back to B30, and count foreward 8 signgroups, accordingly {B30,A01,A02,A03,A04,A05,A06,A07}, and continue with the next 7 signgroups. Make this shift eight times in total for the 61-1 signgroups. A count over will ensure you that each area of 8 and 7 signgroups contains 29 and 31 visible signs by turn! Finally A31.
This was all about the 243 signs which are visible on the Disc in this productive variation of my 244-day prototype calendar.

If you are aware of my interpretation of this hieroglyphic inscription, you'll know that I plead that all signs form part of elements of always two signs. My method thereby determines 70 stem-elements together with 104 incomplete elements, because these only contain a single sign. In other words the inscription is in lack of 104 units. The same figure as the number of reduced elements.
Prototype: 70 x2 stem-coponenets and 104 incomplete elements consequently 104 absent units, plus 17 strokes. -365-.
Variation : 70 x2 stem-components and 103 reduced elements consequently 103 invisible units, plus 18 thorns. -364-.

Imagine a compass card being placed in the middle of the grand-circle, appointing {B30,A01,A02,A03,A04,A05,A06,A07}as the western area, and {A30,B01,B02,B03,B04,B05,B06,B07} as the eastern area. The signgroups in those two corners contain together 31 reduced stems or 31 absent units (if you can possess something absent.) The same pattern repeats itself for the 8 northern and 8 southern signgroups, while it is somehow different with the 7 signgroups sited northwest and the 7 in southwest with 29 units together, and finally for the northeast and southeast signgroups with 29 unit-days, thus forming a fleur-de-lis. As to symmetry, not unlike the pointer figure of the various Maya and Actez calendar stones.
This was my introduction to the missing season of the Phaistos Disc Calendar.


In the above figure "the packed circle" the two spirals on the disc are unfolded to a single "grand circle", which contains the 243-3 visible signs at the rim apart from the three signs of A31
At the same time the absent parts of the 103-1 reduced elements emerge as, previously covered, feathers into a median circle.
Finally an inner circle shows 18 thorns, which are concrete strokes that are made before the clay disc did set.
Every eight part of the circle is made up by alternating 7 and 8 signgroups.
It is important for me to state that this observation of a calendar has never been done before by anyone else, by that simple fact that no-one has thought out earlier that the two dotted dividers in front of A01 and B01 have values as normal signs. This discovery takes you to the conclussion that the signs are not syllables.
Now asking the question: what is then the situation? make you arrive to my discovery of the 22 stem-forms, verified by the gnomonical arrangement.
Definitely the very most plausible interpretation of this famous disc from near Hagia Triada in southern Crete; though overheard!
Important: Do me the favour to go through the consecutive order of the 243 pictographs from a photo of the disc, and compare it to my figure above (the folded arrangement); you'll find, that the two versions agree! This should rightly disarm all skepticism and ignorance. Now is the time to urge you to consider the seriousity of the situation for the sake of everything. -[tmkiiissstttiiilll : iak satta runaR ret ...]-Gørlev stone. *


The divisibility by eleven, through this formular [Commensurable to a 5.5 * n table with an allowed inacurracy on plus/minus 0.5, when n is an unequal number ]:
{5,6,11,16,17,22,27,28,33,38,39,44,49,50,55,60,61}, is continued (far beyond its certification through the gnomonical arrangement with its already omnipresency of eleven) in this " The alternative calendar ". Here I choose to combine 44 consequtive reduced elements into 22 so-called "combies", leaving only 60 reduced elements instead of the otherwise 104. Following these metrical footsteps : _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ . _ .

Carrying the revealed system to a logical conclusion, could be, to consider the 70 stems together with the 22 combined reduced elements, as the one type of elements: contra the 60 reduced elements and the 22 medial absent elements as the second type. Thus forming a periodical alternation between long and shortform elements. The open spaces between the sign-groups would take part in this interaction. The 22 "combies" borrow 44 reduced elements, to become like stems, leaving over 60 of the before 104 reduced elements, but this is compensated for by the 22 absent medial elements. This variant is called the "Alternative calendar".
In princip all eight rows possess 22 elements (the thorns are half elements) when without "open spaces". Also the eight rows each has 29 hieroglyphs, when without the four unpaired stems. Cf "the alternative combi-calendar".

E.F.A.N.K. When the 4 unpaired elements and A07 are outruled. The inscription has 174 signs in its stem-, and combi-elements. Side A has 92 signs in expanded elements. Side B has 82. 46=17+12+17, 41=12+17+12.

The 4 unpaired stems are: UT, OP, IH, BA, If they were removed from the inscription, then 29 x8 =232 signs are left over. 232 +A07 =235 signs (double function as months?).Lunisolar calendars.


A circular variant of (10b). with 2x2 coils for side A and side B

Please compare this arrangement to what you have observed of others attempts to set up a survey over the entire inscription, during the last one-hundred years. and then get in touch with me for a valid publication.

In this variation (with the base of 243 signs with A08 =ZÆBA), I count down from A30 to Bo1. Bo1 is decorated with five initial pearls. This could mean: Advance by five sign-groups at a time. (*) If all the 61 'cartouches' count as two units each with a frame and a vertical line, like in "my nutshell calendar", they could replace my 104 absent units, and the 17 (or 18) thorns . This is of interest because it gives a straight forward outcome with "12 months of five weeks and 29 days". Giving 348 days, plus A31 adding up with 5 more days (+ the initial divider in B01, making the wheel full circle) equal to the so-called lunar year of 354 days. In the right margin 11 signs are set aside. Adding up to 365 unit-days. The famous solar-year!
The 11 signs in the margin are (1) the dot-signs of the two entrances ahead of B01 and A01. -(2) The as well misplaced dove in A23. -(3) The four unpaired stems; out of the 70 stems. Those four stems decide whether it is a shift 29, 31 (30), or a clean 29 day moon-calendar.
Yet another saying reflextion of the inherent calendar inside the Phaistos disc. -Did I mention? that all this was only detectable due to the pre-science of the exact 33 pairs of stems!
(*) The dots could also count for ten units: 10 +((29 x6) +1) x2). Together with 5 days of A31 bringing 365 unit-days The four unpaired stems should then vanish from the calculations. - The dove in A23 will stay
P.S. If you are looking for the exposed internal structure of the inscription "its dual nature", this is not the place. See instead the various points above : especially point 4, which also is aranged in 29 x12 days, and simultaneously reveals the double nature of the whole story. Further on, point 4 has this relation between stem sign-groups and non-stem sign-groups of 290 to 58 (+17) units, 5:1. While in this point 11 the relation is 295 (+11) : 59 units, or 5:1 alike.
In fact I call every-one as witnesses on 'this my latest refinements of this Minoan calendar!', which is based on my 22 stem-forms.

When you, in this faithful situation, have send out one hundred times for assessment (one house at a time) your evident "answer" to the understanding of this very famous artifact, you never try it the "one hundred and one time", this would be an impossibility. Likewise, when let down, my only hope was to consolidate myself the discovery of the 22 stem-forms and their consequences, which I did.

from Andrew Willes biography [Fermat's third theorem: xª +yª =zª, ª>2, can not be done]. This problem withstood for about 350 years [The Phaistos disc theorem: A² +B² +C² =365]. Stood for 100 years (?). -To be called the quadrature of the (calendar) circle. (I made that definition myself) *

What a powerful River!



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